Re: the out_items of python block?

Hi liumaolin,

>     def work(self, input_items, output_items):
>         """example: multiply with constant"""
>         for i in range(10) :

You can't do that: you need to make sure you've got at least 10 output items to fill!

> return len(output_items[0])

Here you tell GNU Radio that you produced `len(output_items[0])` items, where in reality
you produced 10, which might (and will) be less or more than `len(output_items[0])`!

Best regards,
Marcus