> The idea of the u8 data type is that it does a raw dump of the data. So > if you receive it, then cast the buffer as uint32_t *, you'll get your data. OK, I thought I was on the same page until this statement. So I make my output in my verilog code will be 32b, and I can set things up like normal in the CHDR code. Then my XML files will have "byte" (I saw that used somewhere, but I see you called it u8, so I will dothat) as the type so that it will do a raw dump. Then on my receiver side, I set it up to receive a byte, but I typecast it as uint32_t * to get all 32b back out? Am I understanding that right?
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Tuesday, December 8, 2015
Re: [Discuss-gnuradio] U32 type for module output
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