Tuesday, December 8, 2015

Re: [Discuss-gnuradio] U32 type for module output

> The idea of the u8 data type is that it does a raw dump of the data. So  > if you receive it, then cast the buffer as uint32_t *, you'll get your data.  OK, I thought I was on the same page until this statement.      So I make my output in my verilog code will be 32b, and I can set things up  like normal in the CHDR code.  Then my XML files will have "byte" (I saw that   used somewhere, but I see you called it u8, so I will dothat) as the type so  that it will do a raw dump.  Then on my receiver side, I set it up to receive a  byte, but I typecast it as uint32_t * to get all 32b back out?      Am I understanding that right?  

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