On Thu, Aug 4, 2011 at 6:13 PM, Page Jack <jack.page999@gmail.com> wrote:
Hi Colby,
I don't understand why compute RSSI need an IIR filter? as I know the rssi can be compute
like that: (sample[0]*sample[0]+...sample[i]*sample[i]) / (i+1)
Regards!On Thu, Aug 4, 2011 at 2:44 PM, Colby Boyer <colby.boyer@gmail.com> wrote:On Wed, Aug 3, 2011 at 6:30 PM, Page Jack <jack.page999@gmail.com> wrote:
_______________________________________________the code below is in sdr_lib/rssi.v I don't understand especially this line: rssi_int <= #1 rssi_int + abs_adc - rssi_int[25:10];
wire [11:0] abs_adc = adc[11] ? ~adc : adc;
reg [25:0] rssi_int;
always @(posedge clock)
if(reset | ~enable)
rssi_int <= #1 26'd0;
else
rssi_int <= #1 rssi_int + abs_adc - rssi_int[25:10];
assign rssi = rssi_int[25:10];
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It appears to be a clever way to implement a single pole IIR filter. Josh?If you recall an IIR is defined as y[n] = (1-alpha) * y[n-1] + x[n]Since multiplier are expensive in hardware, lets use a multiples of two so you can bit shift, then add and subtract. :D In this case alpha is 2^-10--Colby
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