On 4/10/24 11:29, Fons Adriaensen wrote:
> Both the decimation and 80 size 1024 FFTs per second should be peanuts
> for any modern PC...
>
> And of course you don't need to do the FFT again for every sample,
> it just generates a lot of redundant data.
I understood that if you have a 1024 bin waterfall, it takes that many
samples to fill it and output a vector. With a sample rate of 80, that
means about 12.8 seconds to show one line of the waterfall. Or do I
have that wrong?
(I used 80 samples/sec for simplicity. The actual rate after decimating
from a 1.536 ms/s stream is 93.75.)
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